In trapezoid $ABCD$, $\overline{BC} \parallel \overline{AD}$, $\angle ABD = 105^\circ$, $\angle A = 43^\circ$, and $\angle C = 141^\circ$. Find $\angle CBD$, in degrees.

Answer 1

come on. the angles of any quadrilateral sum to 360

Answer 2

You do aops right? :)

Answer 3

lol when this time of year comes around...
Who even comes across these posts without looking for the answers? XD

Answer 4

does anyone know the answer lol