You must have meant,
"What are (a) the magnitude and (b) the angle (relative to +x) of Vector C "
A = (11.6cos36.5 + 11.6sin36.5) = (appr 9.32, 6.90)
B = (14cos17.1 + 14sin17.1) = (appr13.38 , 4.12)
vector C = (22.71 , 11.02)
magnitude = √22.71^2 + 11.02^2) = 25.24
angle:
tanØ = 11.02/22.71
Ø = 25.88°
In the sum Vector A plus Vector B equals vector C, vector A has a magnitude of 11.6 m and is angled 36.5° counterclockwise from the +x direction, and vector C has a magnitude of 14.0 m and is angled 17.1° counterclockwise from the -x direction. What are (a) the magnitude and (b) the angle (relative to +x) of Vector B.
1 answer