same as your fence really
a + b = 40 so b = 40 - a
P = a b = a(40-a) = 40 a - a^2
dP/da = 40 - 2 a
a = 20
then b = 20
so
20 and 20
In the space below, provide the smaller of the two positive integers that add to 40 and have the largest possible product
2 answers
a + b = 40 so b = 40 - a
P = a b = a(40-a) = 40 a - a^2
dP/da = 40 - 2 a
a = 20
then b = 20
so
20 and 20
P = a b = a(40-a) = 40 a - a^2
dP/da = 40 - 2 a
a = 20
then b = 20
so
20 and 20