Since the opposite angles in a rhombus are congruent, we know that m<2 = m<4. So, m<2 = 140 °.
Since the sum of the angles in a rhombus is 360 °, we can find m<3 by subtracting the sum of m<1 and m<2 from 360:
m<3 = 360 ° - m<1 - m<2
m<3 = 360 ° - 140 ° - 140 °
m<3 = 80 °.
In the rhombus pictured, m<1=140 °
. What are m<2 and the m<3? Please sure all work in order to receive full credit.
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