In the reaction Ca(OH)2 + 2HCL -> CaCl2 + 2H2O: How many kilograms of H2O will be produced when 0.0948 Kg of Ca(OH)2 react with excess hydrochloric acid?
3 answers
Isn't this a regular stoichiometry problem?
yes it is but i need help in how to solve it.
Here is how all of them are worked.
1. Write and balance the equation.
Ca(OH)2 + 2HCl ==> CaCl2 + 2H2O
2. Convert what you have to mols.
mols Ca(OH)2 = grams/molar mass = ? You will need to convert kg to g first.
3. Using the coefficients in the balanced equation, convert mols Ca(OH)2 to mols H2O produced. In this case that is ?mols Ca(OH)2 x (2 mols H2O/1 mol Ca(OH)2) = ?mols Ca(OH)2 x 2/1 = ?
4. Then convert mols H2O to grams. g = mols x molar mass = ? and convert to kg.
Post your work if you get stuck or explain in detail what you don't understand.
1. Write and balance the equation.
Ca(OH)2 + 2HCl ==> CaCl2 + 2H2O
2. Convert what you have to mols.
mols Ca(OH)2 = grams/molar mass = ? You will need to convert kg to g first.
3. Using the coefficients in the balanced equation, convert mols Ca(OH)2 to mols H2O produced. In this case that is ?mols Ca(OH)2 x (2 mols H2O/1 mol Ca(OH)2) = ?mols Ca(OH)2 x 2/1 = ?
4. Then convert mols H2O to grams. g = mols x molar mass = ? and convert to kg.
Post your work if you get stuck or explain in detail what you don't understand.
1 answer