What does the equation tell you? That 89.3 kJ are absorbed when 1 mol (76.1g CS2) are formed. You have 6.33 g; therefore,
89.3 kJ x (6.33/76.1) = ? kJ
In the reaction C(s) + 2S(s) �¨ CS2(l), the change of enthalpy (ƒ¢H) is 89.3 kJ. Calculate the amount of heat absorbed when 6.33 g of carbon disulfide is formed.
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