Question

In the proof that a/b + c/d, where a, b, c, and d are integers and b and d are non-zero, explain why ad+bc/bd is a rational number

By the closure Property, ad + bc and bd are both quotients of integers, and so ad+bc/bd is a quotient of two integers
By the closure property, a quotient of imaginary numbers is a rational number
by the closure property, ad+bc/bd reduces to a whole number, which is a subset of rational numbers
By the closure property, ad + bc and bd are both integers, and so ad+bc/bd is a quotient of two integers

Answer 1

just choose one

Answer 2

To explain why \(\frac{ad + bc}{bd}\) is a rational number when \(a\), \(b\), \(c\), and \(d\) are integers with \(b\) and \(d\) being non-zero:

1. **Definition of Rational Numbers**: A number is considered rational if it can be expressed as a quotient of two integers, where the denominator is not zero.

2. **Numerator \(ad + bc\)**: Here \(ad + bc\) is the result of the addition of two products, \(ad\) and \(bc\). Since \(a\), \(b\), \(c\), and \(d\) are integers, both \(ad\) and \(bc\) are also integers (the product of integers is an integer). Thus, when we add these two integers, \(ad + bc\) is itself an integer.

3. **Denominator \(bd\)**: Since both \(b\) and \(d\) are given to be non-zero integers, their product \(bd\) is also a non-zero integer. This is important because a rational number cannot have a zero denominator.

4. **Combining the Numerator and Denominator**: Now, we have \(\frac{ad + bc}{bd}\). The numerator \(ad + bc\) is an integer, and the denominator \(bd\) is a non-zero integer. Therefore, we are looking at a quotient of two integers.

5. **Conclusion**: Since the quotient of an integer (the numerator) by a non-zero integer (the denominator) satisfies the definition of a rational number, we conclude that \(\frac{ad + bc}{bd}\) is indeed a rational number.

Your original statement seemed to mix concepts, particularly the mention of imaginary numbers. The reasoning based on closure properties of integers regarding addition and multiplication leading to integers is the correct approach here. Thus, the final understanding is that \(\frac{ad + bc}{bd}\) is a rational number because it is a quotient of two integers, where the denominator is non-zero.

Answer 3

The correct statement is:

**By the closure property, \(ad + bc\) and \(bd\) are both integers, and so \(\frac{ad + bc}{bd}\) is a quotient of two integers.**

This clearly indicates that \(\frac{ad + bc}{bd}\) is a rational number because it is the quotient of an integer by a non-zero integer.