The glide ratio of an aircraft is the distance it can travel horizontally divided by the height it descends vertically. To calculate the glide ratio for Air Transat Flight 236, we need to find the horizontal distance traveled and the vertical descent.
Given the problem, we have:
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Vertical descent: 10 kilometers (10,000 meters) altitude initially, and the aircraft had 500 meters of 'spare' altitude when reaching the military base. Therefore, the actual vertical descent is:
\[ \text{Vertical descent} = 10,000 , \text{meters} - 500 , \text{meters} = 9,500 , \text{meters} \]
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Horizontal distance traveled: The problem states that the aircraft was 120 kilometers away from the nearest airport when the second engine failed. To convert kilometers to meters, we have:
\[ \text{Horizontal distance} = 120 , \text{kilometers} = 120,000 , \text{meters} \]
Now, we can calculate the glide ratio as follows:
\[ \text{Glide Ratio} = \frac{\text{Horizontal Distance}}{\text{Vertical Descent}} = \frac{120,000 , \text{meters}}{9,500 , \text{meters}} \]
Calculating this gives:
\[ \text{Glide Ratio} \approx 12.63 \]
Thus, the glide ratio of the Airbus A330 in this scenario is approximately 12.63:1. This means that for every meter it descends, it travels about 12.63 meters forward horizontally.