In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water:

1 answer

The combustion of methane (\(CH_4\)) in the presence of excess oxygen can be represented by the following balanced chemical equation:

\[ CH_4(g) + 2O_2(g) \rightarrow CO_2(g) + 2H_2O(g) \]

In this reaction:

  • One molecule of methane reacts with two molecules of oxygen (\(O_2\)) to produce one molecule of carbon dioxide (\(CO_2\)) and two molecules of water (\(H_2O\)).
  • This reaction is exothermic, meaning it releases heat, and occurs under constant pressure conditions.

If you have any specific questions about this reaction or related concepts, feel free to ask!