force up = 25 sin 25
force down = 5(9.81)
normal force = 5(9.81) - 25 sin 25
pull force = 25 cos 25
back friction force = 4
so
25 cos 25 - 4 = 5 * a
In the picture to the right, a ring pulls a box of mass m = 5.0 kg across a level table. The string pulls with a tension F = 25.0 N at an angle θ = 25˚ above the horizontal. A frictional force of 4.0 N also acts on the box. Calculate a. the normal force on the box. b. the acceleration of the box.
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