Prob(using consultant) = 20/100 = 1/5
prob(NOT using consultant) = 4/5
a) prob(exactly 5 of 15 use con) = C(15,5) (1/5)^5 (4/5)^10 = ...
b) find the probs for exactly 12, exactly 13 ... exactly 15 and add up those 4 cases.
c) find prob(that all 15 use a con) and subtract that from 1
d) What do you think?
e) all yours,
In the past few years, outsourcing overseas has become more frequently used than ever before by U.S. companies. However, outsourcing is not without problems. A recent survey by Purchasing magazine indicates that 20% of the companies that outsource overseas use a consultant. Suppose 15 companies that outsource overseas are randomly selected.
a. What is the probability that exactly five companies that outsource overseas use a consultant?
b. What is the probability that more than eleven companies that outsource overseas use a consultant?
c. What is the probability that none of the companies that outsource overseas use a consultant?
d. What is the probability that between three and seven (inclusive) companies that outsource overseas use a consultant?
e. Construct a graph for this binomial distribution.
2 answers
ok
1 answer