Asked by Letisha

In the parallel spring system, the springs
are positioned so that the 44 N weight
stretches each spring equally. The spring con-
stant for the left-hand spring is 3.6 N/cm and
the spring constant for the righ-hand spring
is 6.4 N/cm.

How far down will the 44 N weight stretch
the springs?
Answer in units of cm.
Answered by bobpursley
The forces are additive.

F1+F2=44N
3.6*x+6.4x=44
solve for x.
There are no AI answers yet. The ability to request AI answers is coming soon!