If all of these are gases you may use a shortcut and use volumes as mols directly.
260 cc NH3 x (4 mols NO/4 mols NH3) = 260 x 1 = ? cc NO.
Do the same with O2 using the coefficients for NH3 and O2.
In the industrial preparation of HNO3, NH3 is burnt in O2 in the presence of a catalyst, according to the following equation;
4NH3 + 502 - 4NO +6HO
If 260ccm3 of NH3 is burnt completely. what volume of O2 is used up and NO is produced
3 answers
I don't actually understand, pls explain more on it
OK. The long way. Almost all stoichiometry problems are worked this way.
1. Write and balance the equation, You have done that.
2. There are 22.4 L in a mole of gas (at STP and this probably is not at STP which is why I used the shortcut).
mols NH3 = 250/22,400 = 0.0112
3. Using the coefficients in the balanced equation, convert mols NH3 to mols NO. That is
0.0112 x (4 mols NO/4 mols NH3) = 0.0112
4. Convert 0.0112 mols NO to cc NO (if you want volume) = 0.0112 x 22,400 = 250 cc. If you want grams NO, which the problems asked for and I didn't show in my first response, grams = mols NO x molar mass NO = 0.0112 x 30 = ? grams.
The shortcut way is faster BECAUSE you see step 1 divides by 22,400 to convert to mols and step 4 multiplies by 22,400 to convert to volume. You can time by not doing those two steps.
1. Write and balance the equation, You have done that.
2. There are 22.4 L in a mole of gas (at STP and this probably is not at STP which is why I used the shortcut).
mols NH3 = 250/22,400 = 0.0112
3. Using the coefficients in the balanced equation, convert mols NH3 to mols NO. That is
0.0112 x (4 mols NO/4 mols NH3) = 0.0112
4. Convert 0.0112 mols NO to cc NO (if you want volume) = 0.0112 x 22,400 = 250 cc. If you want grams NO, which the problems asked for and I didn't show in my first response, grams = mols NO x molar mass NO = 0.0112 x 30 = ? grams.
The shortcut way is faster BECAUSE you see step 1 divides by 22,400 to convert to mols and step 4 multiplies by 22,400 to convert to volume. You can time by not doing those two steps.