In the scenario described, we have several action/reaction force pairs based on Newton's Third Law, which states that for every action, there is an equal and opposite reaction. Here’s how the forces would correspond to the situation:
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Fish (10N):
- Action: The fish exerts a downward force on the water (10N).
- Reaction: The water exerts an equal and opposite force upward on the fish (10N).
So we can assign:
- C. +10N (upward force on the fish)
- D. -10N (downward force exerted by the fish)
-
Water (40N):
- Action: The water exerts a downward force on the aquarium (40N).
- Reaction: The aquarium exerts an equal and opposite force upward on the water (40N).
We can assign:
- E. +70N (the aquarium plus the fish, since 40N + 10N that the fish adds)
- F. -70N (the total downward force on the table)
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Aquarium (20N):
- Action: The aquarium exerts a downward force on the table (20N).
- Reaction: The table exerts an equal and opposite force upward on the aquarium (20N).
So we can assign:
- A. +120N (the total upward force on the table, sum of the forces: 50N from the table + 70N down from water)
- B. -120N (the total downward force acting on the table)
Putting it all together, we have the following action/reaction force pairs:
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Fish on Water:
- C. +10N (water force on fish)
- D. -10N (fish force on water)
-
Water on Aquarium:
- E. +70N (upward force on table)
- F. -70N (downward force on aquarium)
-
Aquarium on Table:
- A. +120N (reaction force from table)
- B. -120N (action force on table)
Thus, the forces are arranged as follows:
- C. +10N (upward force on the fish)
- D. -10N (downward force by the fish)
- E. +70N (from the aquarium)
- F. -70N (downward on the table)
- A. +120N (upward from table forces)
- B. -120N (total forces acting downward on the table)
1 answer