In the image, parallelogram ABCD is dilated in reference to the origin to form parallelogram A'B'C'D'. What is the magnitude of dilation?

Coordinate A (-2,4)
Coordinate B (4,4)
Coordinate C (2,-2)
Coordinate D (-4,-2)
Coordinate A' (-1,2)
Coordinate B' (-2,2)
Coordinate C' (1,-1)
Coordinate D' (-2,-1)

1 answer

To find the magnitude of the dilation from parallelogram ABCD to A'B'C'D', we can analyze the relationship between the corresponding points.

Dilation is defined as the transformation of points in a plane relative to a center point (in this case, the origin) by a scale factor. Mathematically, for a point \( (x, y) \) being dilated to a point \( (x', y') \) in reference to the origin by a scale factor \( k \), this relationship can be expressed as:

\[ (x', y') = (k \cdot x, k \cdot y) \]

We can find the scale factor \( k \) by using the coordinates of corresponding points.

Let's take point A and A':

  • Original point A: \( (-2, 4) \)
  • Dilated point A': \( (-1, 2) \)

Using the formula:

\[ (-1, 2) = (k \cdot -2, k \cdot 4) \]

So we have the equations:

  1. \( k \cdot -2 = -1 \)
  2. \( k \cdot 4 = 2 \)

From the first equation, solving for \( k \): \[ k \cdot -2 = -1 \quad \Rightarrow \quad k = \frac{-1}{-2} = \frac{1}{2} \]

From the second equation, solving for \( k \): \[ k \cdot 4 = 2 \quad \Rightarrow \quad k = \frac{2}{4} = \frac{1}{2} \]

In both cases, we find that \( k = \frac{1}{2} \).

This indicates that the magnitude of dilation from parallelogram ABCD to A'B'C'D' is:

\[ \boxed{\frac{1}{2}} \]

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