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In the following reaction, how many liters of carbon dioxide, CO2, measured at STP, would be produced from the decomposition of 143 g of magnesium carbonate, MgCO3?

MgCO3----MgO+CO2

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for each mole of MgCO3, one gets one 22.4liters CO2.

143g of MgCO3 is how many moles?

answer is 38.0 L

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