In the following reaction, how many grams of ammonia (NH3) will produce 300 grams of N2?

4NH3 + 6NO -> 5N2 + 6H2O

1 answer

Each 4 moles of NH3 produce 5 moles of N2

so, you get

4/5 * 300/14 * 17.03 = 292g NH3