230g of compound is 230/88.15 = 2.609 moles
The balanced equation is
2C5H11OH + 15O2 ----> 10CO2 + 12H2O
So, you will need 15/2 * 2.609 * 6.02*10^23 = 1.78 * 10^25 molecules of O2
1.505*10^21 = 0.0025 moles CO2
So, you'd have produced 12/10 * 0.0025 * 18.02 = 0.054 g H2O
In the following reaction, first find how many oxygen molecules would be used to completely react with 230 grams of pentyl alcohol (C5H11OH)? Then, if exactly 1.505x10^21 carbon dioxide molecules were formed in this reaction, calculate the grams of water formed during this reaction. C5H11OH+O2 ---->CO2+H2O
1 answer