In the first 14.0 s of the reaction, 1.7×10−2 mol of O2 is produced in a reaction vessel with a volume of 0.340 L What is the average rate of the reaction over this time interval? 2 N2O(g) → 2 N2(g)+O2(g)

Question

In the first 14.0  s of the reaction, 1.7×10−2  mol of O2 is produced in a reaction vessel with a volume of 0.340  L What is the average rate of the reaction over this time interval? 2 N2O(g) → 2 N2(g)+O2(g)

DrBob222 · Accepted Answer

time = 14 s change in O2 = 0.017 mols. volume = 0.340 L [O2] = mols/L = 0.017/0.340 = estimated 0.05 M rate = 0.05M/14 s = ?