In any triangle, the sum of all angles is 180 degrees. Since we know that angle AEB is 50 degrees, we can subtract this from 180 to find the total degrees remaining for the other three angles: 180 - 50 = 130 degrees remaining.
Since angles AEC and CEB are supplementary (they form a straight line), their sum is 180 degrees. Therefore, one angle, AEC, must be 130 degrees. Now we have 130 degrees remaining for angle CEB.
Finally, since angles ACD and DCE are also supplementary, their sum is 180 degrees. Therefore, angle ACD is equal to angle CEB, so angle ACD is also 130 degrees.
So the other three angles in the triangle are:
Angle AEC = 130 degrees
Angle CEB = 130 degrees
Angle ACD = 130 degrees
In the figure shown, the m∠AEB = 50 degrees. Find the other three angles.
1 answer
1 answer