weight = m g = 3.72*9.81 = 36.5 N
FR I assume down
FL I assume up
so
FL = 36.5 + FR
moments about left hand = 0
36.5 * 1.54 = FR * 0.653
FR =
then go back and get FL
In the figure below, the CG of the pole held by the pole vaulter is 1.54 m from the left hand, and the hands are 0.653 m apart. (Assume the vaulting pole has a mass of 3.72 kg.)
-Calculate the force (in N) exerted by his right hand. (Enter the magnitude.)
-Calculate the force (in N) exerted by his left hand. (Enter the magnitude.)
1 answer