(a.)
F applied - m(a) = Frictional force, remember negative component.
(b.)
Torque = Frictional force*(radius)
Inertia = Torque/alpha
alpha= Acom/Radius= A/R
In the figure below, a constant horizontal force Fapp of magnitude 18 N is applied to a wheel of mass 12 kg and radius 0.50 m. The wheel rolls smoothly on the horizontal surface, and the acceleration of its center of mass has magnitude 0.50 m/s2. What is the friciotnal force on the wheel
2 answers
Sicko Mode or Mo Bamba