To analyze the modified equation with \( 3H_2 \):
If we take the original equation:
\[ 2H_2 + O_2 \rightarrow 2H_2O \]
By changing \( 2H_2 \) to \( 3H_2 \), we get:
\[ 3H_2 + O_2 \rightarrow ? \]
To balance this new equation, we need to determine how many water molecules can be produced from \( 3H_2 \). Each water molecule requires \( 2H \) atoms. Therefore, with \( 3H_2 \) providing \( 6H \) atoms:
\[ 3H_2 + O_2 \rightarrow 3H_2O \]
Now, we also need to note that for \( 3H_2O \), we need \( \frac{3}{2}O_2 \) (which is equivalent to 1.5 O2 molecules).
Balanced equation:
\[ 3H_2 + \frac{3}{2}O_2 \rightarrow 3H_2O \]
This means we would need 1.5 molecules of \( O_2 \), but because we typically do not express fractions in balanced equations, we can multiply everything by 2 to avoid fractions:
\[ 6H_2 + 3O_2 \rightarrow 6H_2O \]
Now, examining the options given in the question, we can clarify:
- The result of the equation will be the same. (Incorrect; changing \( H_2 \) changes the products.)
- Each oxygen molecule will combine with 2 hydrogen molecules with no leftover molecules. (Incorrect; that applies to the original equation but not when using 3 \( H_2 \)).
- It is not possible to produce water without leftover molecules. (Incorrect; we can produce water with no leftovers if balanced correctly.)
- The equation will produce three molecules of water. (Correct; it produces 3 \( H_2O \).)
Thus, the correct statement is:
The equation will produce three molecules of water.