To balance the modified equation where you have 3H2 instead of 2H2, we start with the original reaction:
Original:
\[ 2 H_2 + O_2 \rightarrow 2 H_2O \]
If we change it to 3H2, the new equation looks like this:
New:
\[ 3 H_2 + O_2 \rightarrow ? H_2O \]
To balance the new equation, we recognize that each water molecule (H2O) requires 2 hydrogen atoms. If we have 3 H2 (which gives us 6 hydrogen atoms), we can produce:
\[ \frac{6 \text{ H}}{2 \text{ H per H}_2O} = 3 \text{ H}_2O \]
The balanced equation will be:
\[ 3 H_2 + 3 O_2 \rightarrow 3 H_2O \]
Now, examining the provided statements, the correct statement is:
- The equation will produce three molecules of water.
Therefore, this statement accurately reflects the result of the balanced equation after changing to 3 H2.