In the drawing, the weight of the block on the table is 380 N and that of the hanging block is

Question

175 N. Ignore all frictional effects, and assuming the pulley to be massless. What is the
acceleration of the two block?

Answer 1

m₁g+m₂g =(m₁+m₂)g =380+175=555
(m₁+m₂) =555/g=56.6 kg
m₁a =T
m₂a=-T+m₂g
m₂a = - m₁a +m₂g
a=(m₂g)/(m₁+m₂) =
=175/56.6=3.1 m/s²