in the diagram, the balls velocity is 6 m/s, and the height of the ramp is 1 m. what will the balls velocity be at the top of the ramp? ignore friction.

Answer 1

KE at the start: 1/2 mv^2 = 18m
PE at the top: mgh = 9.8m
difference: 8.2m = 1/2 mv^2
so find v,

Answer 2

4 m/s is the correct answer

Answer 3

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