In the diagram,Q is SW of P R is NW of P ∆QPT is 165°.What is the bearing of T from P?

Answer 1

first, what does "∆QPT is 165°" mean?
Do you mean ∡QPT is 165° ?
If so, then
If by SW and NW you mean bearings from P of
225° and 315°, then ∡QPR = 90°
so ∡RPT = 75°, making the bearing of T from P 30°

If I parsed things wrong, then draw you own diagram and mark the angles you need.