To find the measure of angle \( DAB \), we start by using the information given in the problem. We know the following:
- \( AD \perp DC \) implies that angle \( ADC = 90^\circ \).
- \( m\angle CAB = 78^\circ \).
- \( m\angle C = 55^\circ \).
We will use the facts about the angles around point \( A \).
In triangle \( ACD \):
- The sum of the angles in triangle \( ACD \) is \( 180^\circ \).
- We have \( m\angle ACD = 55^\circ \) and \( m\angle ADC = 90^\circ \).
Let \( m\angle DAB \) be represented as \( x \). From the angle sum property, we can write:
\[ m\angle DAC + m\angle ACD + m\angle ADC = 180^\circ \]
Substituting the known values:
\[ x + 55^\circ + 90^\circ = 180^\circ \]
Combining the angles on the left side:
\[ x + 145^\circ = 180^\circ \]
Now, we can solve for \( x \):
\[ x = 180^\circ - 145^\circ \] \[ x = 35^\circ \]
Therefore, \( m\angle DAB = 35^\circ \).
So, the measure of angle \( DAB \) is \( \boxed{35^\circ} \).