In the diagram below, start overline, A, D, end overline, is perpendicular to, start overline, D, C, end overline, comma

AD

DC
, m, angle, C, equals, 55, degreesm∠C=55

and m, angle, C, A, B, equals, 78, degrees, .m∠CAB=78

. Find m, angle, D, A, B, .m∠DAB.

1 answer

To find the measure of angle \( DAB \), we start by using the information given in the problem. We know the following:

  • \( AD \perp DC \) implies that angle \( ADC = 90^\circ \).
  • \( m\angle CAB = 78^\circ \).
  • \( m\angle C = 55^\circ \).

We will use the facts about the angles around point \( A \).

In triangle \( ACD \):

  1. The sum of the angles in triangle \( ACD \) is \( 180^\circ \).
  2. We have \( m\angle ACD = 55^\circ \) and \( m\angle ADC = 90^\circ \).

Let \( m\angle DAB \) be represented as \( x \). From the angle sum property, we can write:

\[ m\angle DAC + m\angle ACD + m\angle ADC = 180^\circ \]

Substituting the known values:

\[ x + 55^\circ + 90^\circ = 180^\circ \]

Combining the angles on the left side:

\[ x + 145^\circ = 180^\circ \]

Now, we can solve for \( x \):

\[ x = 180^\circ - 145^\circ \] \[ x = 35^\circ \]

Therefore, \( m\angle DAB = 35^\circ \).

So, the measure of angle \( DAB \) is \( \boxed{35^\circ} \).