In the chlorine titration of a solution prepared by the dissolution of 0.2110 g of commercial hypochlorite was spent 19.50 ML of sodium thiosulphate solution 0.1002 mol/L. Calculate the percentage of chlorine (35.45 g/mol) in this sample
3 answers
Did you add KI and titrate the liberated I2 with Na2S2O3?
yes
I assume you want percent Cl2 (note that is 70.9 g/mol).
Cl2 + 2I^- ==> 2Cl^- + I2
OCl^- + 2I^- + 2H^+ ==> I2 + Cl^- + H2O
I2 + 2S2O3^2- ==> S4O6^2- + 2I^-
mols S2O3^2- => M x L = ?
mols S2O3^2- x 1/2 = mols I2 = mols Cl2
grams Cl2 = mols Cl2 x molar mass Cl2.
% Cl2 = (g Cl2/mass sample)*100 = ?
Cl2 + 2I^- ==> 2Cl^- + I2
OCl^- + 2I^- + 2H^+ ==> I2 + Cl^- + H2O
I2 + 2S2O3^2- ==> S4O6^2- + 2I^-
mols S2O3^2- => M x L = ?
mols S2O3^2- x 1/2 = mols I2 = mols Cl2
grams Cl2 = mols Cl2 x molar mass Cl2.
% Cl2 = (g Cl2/mass sample)*100 = ?