To solve this problem, we need to determine the mass of CO2 produced by subtracting the mass of CaO formed from the starting mass of CaCO3.
Mass of CaCO3 = 24.8 g
Mass of CaO formed = 13.9 g
Mass of CO2 produced = Mass of CaCO3 - Mass of CaO formed
= 24.8 g - 13.9 g
= 10.9 g
Therefore, the mass of CO2 gas that escaped during the reaction is 10.9 g.
The correct answer is 10.9 g.
In the chemical reaction, Calcium carbonate (CaCO3) was heated to form two new substances: Calcium oxide (CaO) and Carbon dioxide (CO2).
A student heated 24.8 g of CaCO3. After the reaction, they measured 13.9 g of CaO. What was the mass of the CO2 gas that escaped during the reaction?
Question 1 options:
24.8 g
38.7 g
1.78 g
10.9 g
1 answer
1 answer