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in the 74 s after lift-off, the shuttle challenger travels 36 km. assume constant acceleration, calculate

a) the acceleration of the shuttle in m/s^2.

b) the speed of the shuttle in km/h after 74s.

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a) d = 1/2 a t^2 ... 36 = 1/2 a 74^2

b) it starts from rest ... so , v = 2 (36 km / 74 s)
... convert km/s to km/hr ... multiply by 3600 s/hr

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