Since the diagonals bisect the vertex angles, if ∠K is obtuse, ∠PKE cannot be just 16°.
Anyway, to solve this just remember that two consecutive angles of a rhombus are supplementary, so if half of one of them is 16°, half of the next one is 90-16=74°
The diagonals bisect each other, forming four congruent triangles.
In rhombus MPKN with an obtuse angle K the diagonals intersect each other at point E. The measure of one of the angles of a ∆PKE is equal 16°. Find the measures of all angles of ∆PKE and ΔPMN.
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