diagonals of a rhombus are perpendicular bisectors of each other
so, the slope of BD = -1/(3/5) = -5/3
In rhombus ABCD, diagonals AC and BD are drawn. If the rhombus is graphed on a coordinate plane the slope of AC is 3/5. What is the slope of BD? Explain how you know.
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It sure did! Thank you! :)
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