IN RECTANGLEABCD, AB=25CM ,BC=15CM.IN WHAT RATIO DOES BISECTOR OF ANGLE CDIVIDES AB?
2 answers
IN RECTANGLE ABCD ,AB=25CM ,BC=15CM.IN WHAT RATIO DOES BISECTOR OF ANGLE C DIVIDES AB?
Since the bisector meets BC at a 45° angle,
CB=PB = 15
so AP=25-15=10
CB=PB = 15
so AP=25-15=10