IN RECTANGLEABCD, AB=25CM ,BC=15CM.IN WHAT RATIO DOES BISECTOR OF ANGLE CDIVIDES AB?

Answer 1

IN RECTANGLE ABCD ,AB=25CM ,BC=15CM.IN WHAT RATIO DOES BISECTOR OF ANGLE C DIVIDES AB?

Answer 2

Since the bisector meets BC at a 45° angle,

CB=PB = 15
so AP=25-15=10