In rectangle ABCD, AD=BC=5units. Diagnals AC and BD, each of length 10 units, intersect at E. What is the degree measure of angle AEB?

Question

THANKSS

Answer 1

look at the diagram. Drop a line from E to AB. E is in the center of the rectangle, so if angle AEB=θ,

tan(θ/2) = (10/2) / (5/2) = 2
θ/2 = 63.4°
θ = 126.8°