To determine the probability of producing a homozygous dominant (BB) offspring from a cross between two rabbits with the genotype Bb, we can use a Punnett square.
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List the alleles from each parent:
- Parent 1 (Bb): B, b
- Parent 2 (Bb): B, b
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Set up a Punnett square:
B b
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B | BB | Bb |
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b | Bb | bb |
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Analyze the outcomes:
- BB: 1 (homozygous dominant)
- Bb: 2 (heterozygous)
- bb: 1 (homozygous recessive)
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Total combinations: 4
- BB = 1
- Bb = 2
- bb = 1
The probability of producing a homozygous dominant (BB) offspring is the number of BB outcomes divided by the total number of outcomes:
\[ \text{Probability of BB} = \frac{1}{4} \]
Thus, the correct answer is:
C 1 4