It's a rhombus if the diagonal bisects the angles. So, if
2x+4 = 5x-11
the ABCD is a rhombus
in quadrilateral ABCD AC is a diagonol, m<ACD=2x+4 and m<ACB=5x-11 what proves ABCD a rhombus
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^^^ is correct
indeed
how do you work out x ?
A decade later we still looking for the right answer lol
3 answers