Question 17:
If a heterozygous tall pea plant (Tt) is crossed with a homozygous recessive short pea plant (tt), we can create a Punnett square:
T t
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t | Tt | tt |
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t | Tt | tt |
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From the Punnett square, we see the following results:
- 2 Tt (tall)
- 2 tt (short)
Since there are 2 tall plants and 2 short plants, this means 50% of the offspring are expected to be tall.
Answer: 50%
Question 18:
In this question, a black chicken (BB) is crossed with a white chicken (WW) and incomplete dominance is observed. Incomplete dominance means that the offspring will be a blend of the two phenotypes.
Therefore, all offspring will display a gray phenotype (since black and white mix to give gray).
Answer: All gray
Question 19:
In cattle, coat color is controlled by codominant alleles. A red-coated cow (RR) is crossed with a white-coated bull (WW). With codominance, both traits appear in the phenotype without blending.
Thus, the expected phenotypes of the offspring will be red and white coats, since both alleles express themselves.
Answer: Red and white coat
Question 20:
For the mRNA transcription from the given DNA sequence (TAC CGC CCC), you first need to transcribe the DNA into mRNA. The base pairing occurs as follows:
- A pairs with U (in RNA, T in DNA is replaced with U)
- T pairs with A
- C pairs with G
- G pairs with C
Given the DNA sequence:
- TAC -> AUG (mRNA)
- CGC -> GCG (mRNA)
- CCC -> GGG (mRNA)
So the resulting mRNA sequence is:
- AUG GCG GGG
Now, using a codon chart to identify the corresponding amino acids:
- AUG = Methionine (Met)
- GCG = Alanine (Ala)
- GGG = Glycine (Gly)
Thus, the complete response is:
mRNA: AUG GCG GGG
Amino Acid: Met Ala Gly