In pea plants, tall plants (T) are dominant over short plants (t). If a heterozygous tall pea plant is crossed with a homozygous recessive short pea plant, what percentage of the offspring is expected to be tall? (HINT: set up a Punnett Square).(1 point)

Question

Responses

0%
0%

25%
25%

50%
50%

75%

Answer 1

To solve this problem, we can set up a Punnett Square to determine the expected genotypes and phenotypes of the offspring from the cross between a heterozygous tall pea plant (Tt) and a homozygous recessive short pea plant (tt).

1. Parental Genotypes:

   • Tall plant (heterozygous): Tt
   • Short plant (homozygous recessive): tt

2. Gametes:

   • The tall plant (Tt) can produce two types of gametes: T and t.
   • The short plant (tt) can only produce one type of gamete: t.

3. Punnett Square Setup:

         T        t
      ----------------
     |   Tt   |   tt   |
     |--------|--------|
     |   Tt   |   tt   |

4. Offspring Genotypes from the Punnett Square:

   • 2 Tt (tall)
   • 2 tt (short)

5. Percentage of Tall Offspring:

• There are a total of 4 offspring (2 Tt + 2 tt).
• The proportion of tall offspring (Tt) out of the total is 2 tall (Tt) out of 4 total.

Therefore, the percentage of the offspring expected to be tall is: \[ \frac{2 \text{ tall}}{4 \text{ total}} \times 100% = 50% \]

Thus, the correct response is: 50%.