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In parallelogram JKLM , diagonals KM and JL meet at point N . The length of KM is equal to 5x+1 units. The length of NM is equa...Question
In parallelogram JKLM , diagonals KM and JL meet at point N . The length of KM is equal to 5x+1 units. The length of NM is equal to 2x+9 units. What is the value of x?
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Answered by
GPT-4o mini
In a parallelogram, the diagonals bisect each other. Therefore, the length of diagonal KM is twice the length of segment NM.
Let’s denote the lengths mathematically. We have:
- Length of \( KM = 5x + 1 \)
- Length of \( NM = 2x + 9 \)
Since N is the midpoint of KM, we have:
\[
NM = \frac{1}{2} KM
\]
Substituting the expressions for \( KM \) and \( NM \) into the equation gives:
\[
2x + 9 = \frac{1}{2}(5x + 1)
\]
To eliminate the fraction, multiply both sides by 2:
\[
2(2x + 9) = 5x + 1
\]
Distributing on the left side:
\[
4x + 18 = 5x + 1
\]
Now, let’s solve for \( x \). First, subtract \( 4x \) from both sides:
\[
18 = 5x - 4x + 1
\]
This simplifies to:
\[
18 = x + 1
\]
Now, subtract 1 from both sides:
\[
17 = x
\]
Thus, the value of \( x \) is:
\[
\boxed{17}
\]
Let’s denote the lengths mathematically. We have:
- Length of \( KM = 5x + 1 \)
- Length of \( NM = 2x + 9 \)
Since N is the midpoint of KM, we have:
\[
NM = \frac{1}{2} KM
\]
Substituting the expressions for \( KM \) and \( NM \) into the equation gives:
\[
2x + 9 = \frac{1}{2}(5x + 1)
\]
To eliminate the fraction, multiply both sides by 2:
\[
2(2x + 9) = 5x + 1
\]
Distributing on the left side:
\[
4x + 18 = 5x + 1
\]
Now, let’s solve for \( x \). First, subtract \( 4x \) from both sides:
\[
18 = 5x - 4x + 1
\]
This simplifies to:
\[
18 = x + 1
\]
Now, subtract 1 from both sides:
\[
17 = x
\]
Thus, the value of \( x \) is:
\[
\boxed{17}
\]
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