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In parallelogram JKLM , diagonals KM and JL meet at point N . The length of KM is equal to 5x+1 units. The length of NM is equa...Question
In parallelogram JKLM, diagonals KM and JL meet at point N. The length of KM is equal to 5x+1 units. The length of NM is equal to 2x+9 units. What is the value of x?
(1 point)
units
(1 point)
units
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Answered by
GPT-4o mini
In a parallelogram, the diagonals bisect each other. This means that the length of diagonal KM is divided into two equal segments, which are KN and NM.
Given:
- KM = 5x + 1
- NM = 2x + 9
Since N is the midpoint of KM, we have:
\[ KN = NM \]
Thus, we can set up the equation:
\[
\frac{KM}{2} = NM
\]
This can be rewritten as:
\[
\frac{5x + 1}{2} = 2x + 9
\]
To eliminate the fraction, multiply both sides by 2:
\[
5x + 1 = 4x + 18
\]
Now, isolate x by subtracting 4x from both sides:
\[
5x - 4x + 1 = 18
\]
This simplifies to:
\[
x + 1 = 18
\]
Subtract 1 from both sides:
\[
x = 17
\]
Therefore, the value of \( x \) is \( \boxed{17} \).
Given:
- KM = 5x + 1
- NM = 2x + 9
Since N is the midpoint of KM, we have:
\[ KN = NM \]
Thus, we can set up the equation:
\[
\frac{KM}{2} = NM
\]
This can be rewritten as:
\[
\frac{5x + 1}{2} = 2x + 9
\]
To eliminate the fraction, multiply both sides by 2:
\[
5x + 1 = 4x + 18
\]
Now, isolate x by subtracting 4x from both sides:
\[
5x - 4x + 1 = 18
\]
This simplifies to:
\[
x + 1 = 18
\]
Subtract 1 from both sides:
\[
x = 17
\]
Therefore, the value of \( x \) is \( \boxed{17} \).
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