Asked by Maxpoun

In parallelogram DEFG, DH =x+4, HF =3y, GH =3x-1, and HE =5y+3. Find the values of x and y. How long is DF?

Answers

Answered by oobleck
Where is H?
opposite sides have the same length, and the diagonals bisect each other.
That should get you started.
Answered by Bosnian
H = midpoint of parallelogram

In this point the diagonals DF and GE of a parallelogram bisect each other.

By definition of parallelogram:

DH = HF

x + 4 = 3 y

and

GH = HE

3 x - 1 = 5 y + 3

Now you must solve system:

x + 4 = 3 y

3 x - 1 = 5 y + 3
_____________

Isolate x in equation:

x + 4 = 3 y

Subtract 4 to both sides

x = 3 y - 4

Put this value in equation:

3 x - 1 = 5 y + 3

3 ∙ ( 3 y - 4 ) - 1 = 5 y + 3

9 y - 12 - 1 = 5 y + 3

9 y - 13 = 5 y + 3

Subtract 5 y to both sides

4 y - 13 = 3

Add 13 to both sides

4 y = 16

y = 16 / 4

y = 4

x = 3 y - 4

x = 3 ∙ 4 - 4

x = 12 - 4

x = 8

The solutions are:

x = 8 , y = 4

Now:

DH = x + 4 , HF = 3 y

DH = 8 + 4 , HF = 3 ∙ 4

DH = 12 , HF = 12

DF = DH + HF

DF = 12 + 12

DF = 24
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