In parallelogram DEFG, DH = x + 1, HF = 3y, GH = 3x – 4, and HE = 5y + 1. Find the values of x and y.

The parallelogram has D at the top left E at the top right, G at the bottom left and and F at the bottom right with H in the middle.

Thank You ^0^

13 answers

Since the diagonals bisect each other,

x+1 = 3y
3x-4 = 5y+1

x - 3y = -1
3x - 5y = 5

3x - 9y = -3
3x - 5y = 5

4y = 8
y=2
x=5
THank You :) I appreciate your help! :)
x = 5 and y = 2 does not work, I have tried.
yes it does work
It adds up 5+1=6
3 x 2=6
3(5)-4=11
5(2)+1=11
So they are correct.
How'd he get x=5, though?
how did he get 9y
Thanks Steve
holy crap it's been a decade and we're still struggling on the same exact questions
bruh this is trash, no wonder brainy is better
LOOOOOOL sdjf you funny and also right
BROO why is this question even a thingg, ITS BEEN A DECADE AND WE STILL HAVENT GOT IT LOLL
X = 5
Y = 2