What are you titrating the NaOCl with?
H2O2 same question.
In our lab, the data consists of
1. Volume of NaOCl (mL): Trial 1= 10 ml & Trial 2= 10 mL. How can we find the concentration (Molarity), what would the calculated value be?
2. Volume of H2O2 (mL): Trial 1= 1/ml & Trial 2= 1/mL. How can we find the given value for concentration (Molarity)
4 answers
bleach is what NaOCl and H2O2 is being titrated with
Here is what I did, but I'm not sure.
1. 10 g / 74.44 g NaOCl = 0.134/0.01 L = 13.4 which is the calculated value for NaOCl
2. 11 g/34.0147 = 0.323/0.011 L = 29.4 M. for the Given value of H2O2. Is this correct?
1. 10 g / 74.44 g NaOCl = 0.134/0.01 L = 13.4 which is the calculated value for NaOCl
2. 11 g/34.0147 = 0.323/0.011 L = 29.4 M. for the Given value of H2O2. Is this correct?
You didn't answer my question. I know you are titrating bleach and H2O2. What are you titrating it with and what is the concentration of the material with which you are titrating it.
1 answer