Asked by B
In our lab, the data consists of
1. Volume of NaOCl (mL): Trial 1= 10 ml & Trial 2= 10 mL. How can we find the concentration (Molarity), what would the calculated value be?
2. Volume of H2O2 (mL): Trial 1= 1/ml & Trial 2= 1/mL. How can we find the given value for concentration (Molarity)
1. Volume of NaOCl (mL): Trial 1= 10 ml & Trial 2= 10 mL. How can we find the concentration (Molarity), what would the calculated value be?
2. Volume of H2O2 (mL): Trial 1= 1/ml & Trial 2= 1/mL. How can we find the given value for concentration (Molarity)
Answers
Answered by
DrBob222
What are you titrating the NaOCl with?
H2O2 same question.
H2O2 same question.
Answered by
B
bleach is what NaOCl and H2O2 is being titrated with
Answered by
B
Here is what I did, but I'm not sure.
1. 10 g / 74.44 g NaOCl = 0.134/0.01 L = 13.4 which is the calculated value for NaOCl
2. 11 g/34.0147 = 0.323/0.011 L = 29.4 M. for the Given value of H2O2. Is this correct?
1. 10 g / 74.44 g NaOCl = 0.134/0.01 L = 13.4 which is the calculated value for NaOCl
2. 11 g/34.0147 = 0.323/0.011 L = 29.4 M. for the Given value of H2O2. Is this correct?
Answered by
DrBob222
You didn't answer my question. I know you are titrating bleach and H2O2. What are you titrating it with and what is the concentration of the material with which you are titrating it.
There are no AI answers yet. The ability to request AI answers is coming soon!