so she has 500 yards to go, 2 min, her velocity at start is 1200yards/10 min
Vf^2=Vi^2+2ad
So vf=vi+at
(vi+at)^2=vi^2 + ad
Determine vi more accurately than I did above, convert it to m/s, then solve for t given max a.
If no, then put t in as 120sec, and solve for a.
In order to pass a physical education class at a university, a student must run 1.0 mi in 12 min. After running for 10 min, she still has 500 yd to go. If her maximum acceleration is 0.15 m/s2, can she make it? If the answer is no, determine what acceleration she would need to be successful.
3 answers
dfsa
yes