To find the time it takes for a fighter jet to reach takeoff speed from a starting velocity of 0 m/s, we can use the equation of motion that relates acceleration, final velocity, initial velocity, and time. The equation is:
\[ v = u + at \]
Where:
- \( v \) is the final velocity (takeoff speed),
- \( u \) is the initial velocity,
- \( a \) is the acceleration,
- \( t \) is the time.
Given:
- Final velocity \( v = 85 , \text{m/s} \)
- Initial velocity \( u = 0 , \text{m/s} \)
- Acceleration \( a = 11.05 , \text{m/s}^2 \)
We can substitute these values into the equation:
\[ 85 , \text{m/s} = 0 , \text{m/s} + (11.05 , \text{m/s}^2) \cdot t \]
This simplifies to:
\[ 85 = 11.05t \]
Next, we will solve for \( t \):
\[ t = \frac{85}{11.05} \]
Calculating the right side:
\[ t \approx 7.69 , \text{s} \]
Thus, it will take approximately 7.69 seconds for the fighter jet to reach takeoff speed of 85 m/s from a starting velocity of 0 m/s with an acceleration of 11.05 m/s².
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