To solve the problem, we need to multiply the probability of a single adult having health insurance by itself six times since we want to find the probability that all six adults selected have health insurance.
Let the probability of an adult having health insurance be denoted as P(A). Given that 70% of adults have health insurance, P(A) = 0.70.
The probability that all six adults have health insurance, denoted as P(all six), can be calculated as follows:
P(all six) = P(A) * P(A) * P(A) * P(A) * P(A) * P(A)
P(all six) = 0.70 * 0.70 * 0.70 * 0.70 * 0.70 * 0.70
P(all six) = 0.70^6 ≈ 0.1176
Therefore, the probability that all six adults selected at random from the town have health insurance is approximately 0.1176 or 11.76%.
In one town, 70% of adults have health insurance. What is the probability that 6 adults selected at random from the town all have health insurance?
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