In this scenario, we have a long-tailed mouse that is heterozygous (meaning it has one long tail allele and one short tail allele, represented as "L" for long and "l" for short) mating with a short-tailed mouse (which must be homozygous recessive, represented as "ll").
The possible genotypes of the offspring can be determined using a Punnett square:
- The long-tailed mouse (Ll) can produce two types of gametes: L and l.
- The short-tailed mouse (ll) can produce only one type of gamete: l.
Now, we can set up the Punnett square as follows:
l l
______________
L | Ll | Ll |
|______________|
l | ll | ll |
|______________|
From this, we can see the possible offspring genotypes:
- 50% (2 out of 4) will be Ll (long-tailed)
- 50% (2 out of 4) will be ll (short-tailed)
Thus, the chances of having offspring with short tails (ll) is 50%.
The correct response is:
50%