To find the solution of the equations \((7/2)x - (9/2) = 2y\) and \(4y = 7x - 9\), we can start by rewriting both equations in slope-intercept form (\(y = mx + b\)).
For the first equation:
\[ (7/2)x - (9/2) = 2y \] To isolate \(y\), divide both sides by 2: \[ y = \frac{(7/2)x - (9/2)}{2} \] Simplifying gives: \[ y = \frac{7}{4}x - \frac{9}{4} \]
For the second equation:
\[ 4y = 7x - 9 \] Now, divide both sides by 4 to express \(y\): \[ y = \frac{7}{4}x - \frac{9}{4} \]
Comparing the two equations:
Both equations simplify to: \[ y = \frac{7}{4}x - \frac{9}{4} \] Since both equations represent the same line, this means they have an infinite number of solutions (every point on that line is a solution to both equations).
Conclusion:
The correct response is: an infinite number of solutions.