In​ March, a family starts saving for a vacation they are planning for the end of August. The family expects the vacation to cost ​$1364. They start with ​$125. At the beginning of each month they plan to deposit 20​% more than the previous month. Will they have enough money for their​ trip? If​ not, how much more do they​ need?

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Part 1
Select the correct answer below​ and, if​ necessary, fill in the answer box within your choice.
A.
​No, they need ​$
  
enter your response here more. ​(Round up to the nearest​ dollar.)
B.
​Yes, they will have enough money.

5 answers

To determine whether the family will have enough money for their vacation, let's calculate their total savings for the months of March through August.

  1. Initial Savings: $125
  2. Expected Cost of Vacation: $1364
  3. Monthly Deposits: They will deposit 20% more each month than the previous month.

Let's calculate the deposits for each month:

  • Month 1 (March):
    • Deposit = \( x_1 \)
  • Month 2 (April):
    • Deposit = \( x_2 = x_1 \times 1.2 \)
  • Month 3 (May):
    • Deposit = \( x_3 = x_2 \times 1.2 = x_1 \times 1.2^2 \)
  • Month 4 (June):
    • Deposit = \( x_4 = x_3 \times 1.2 = x_1 \times 1.2^3 \)
  • Month 5 (July):
    • Deposit = \( x_5 = x_4 \times 1.2 = x_1 \times 1.2^4 \)
  • Month 6 (August):
    • Deposit = \( x_6 = x_5 \times 1.2 = x_1 \times 1.2^5 \)

We will also need to recognize that they can choose an initial deposit amount. If we denote the initial deposit in March as \( x_1 \), then their deposits for these six months will be:

  • March: \( x_1 \)
  • April: \( x_1 \times 1.2 \)
  • May: \( x_1 \times 1.2^2 \)
  • June: \( x_1 \times 1.2^3 \)
  • July: \( x_1 \times 1.2^4 \)
  • August: \( x_1 \times 1.2^5 \)

The total amount saved by the end of August becomes:

\[ \text{Total Savings} = 125 + x_1 + x_1(1.2) + x_1(1.2^2) + x_1(1.2^3) + x_1(1.2^4) + x_1(1.2^5) \]

This can be simplified using the formula for the sum of a geometric series, \( S_n = a \frac{(1-r^n)}{(1-r)} \) where \( a \) is the first term, \( r \) is the common ratio, and \( n \) is the number of terms.

Here:

  • \( a = x_1 \)
  • \( r = 1.2 \)
  • \( n = 6 \)

The sum of deposits made will then be:

\[ S = x_1 \frac{(1 - 1.2^6)}{(1 - 1.2)} = x_1 \frac{(1 - 2.985984)}{-0.2} \approx x_1 \cdot 9.92992 \]

Thus, adding the initial $125 to the sum of the deposits gives:

\[ \text{Total Savings} = 125 + 9.92992 x_1 \]

To ensure they have enough, this total must be at least $1364:

\[ 125 + 9.92992 x_1 \geq 1364 \]

Isolating \( x_1 \):

\[ 9.92992 x_1 \geq 1364 - 125 \] \[ 9.92992 x_1 \geq 1239 \] \[ x_1 \geq \frac{1239}{9.92992} \approx 124.569 \]

Thus, to know how much money they need for their deposits starting at March, they would need to start depositing at least:

\[ x_1 \approx 125.569 \text{ (rounded up to } 126\text{)} \]

Now, let's check how much they would actually have if they started with the minimum required (126):

After checking with \( x_1 = 126 \):

  • March: 126
  • April: 151.2
  • May: 181.44
  • June: 217.728
  • July: 261.2736
  • August: 313.52832

Total =

\[ 125 + 126 + 151.2 + 181.44 + 217.728 + 261.2736 + 313.52832 \approx 1375.60192 \]

This means they would have:

\( 1375.60192 - 1364 = 11.60192 \)

Thus, they can actually afford their trip with \( x_1 \approx 126 \).

Conclusion

Answer B: Yes, they will have enough money.

wrong

Apologies for the confusion in my previous calculations. Let's go through the problem step by step again to make sure we get the correct outcome.

Given:

  • Initial amount = $125
  • Vacation cost = $1364
  • The monthly deposit increases by 20% starting at \( x_1 \) in March.

Let’s denote the initial deposit (which we will find) as \( x_1 \).

Monthly Deposits:

  1. Month 1 (March): Deposit = \( x_1 \)
  2. Month 2 (April): Deposit = \( x_1 \times 1.2 \)
  3. Month 3 (May): Deposit = \( x_1 \times 1.2^2 \)
  4. Month 4 (June): Deposit = \( x_1 \times 1.2^3 \)
  5. Month 5 (July): Deposit = \( x_1 \times 1.2^4 \)
  6. Month 6 (August): Deposit = \( x_1 \times 1.2^5 \)

Total Savings Calculation:

The total savings by the end of August can be expressed as: \[ \text{Total Savings} = 125 + x_1 + x_1(1.2) + x_1(1.2^2) + x_1(1.2^3) + x_1(1.2^4) + x_1(1.2^5) \]

This can be simplified using the formula for the sum of a geometric series: \[ S_n = a \frac{(1 - r^n)}{(1 - r)} \] where:

  • \( a = x_1 \)
  • \( r = 1.2 \)
  • \( n = 6 \)

Sum of Deposits:

The sum of deposits from March to August is: \[ \text{Deposit Total} = x_1 \frac{(1 - 1.2^6)}{(1 - 1.2)} = x_1 \frac{(1 - 2.985984)}{-0.2} \approx x_1 \cdot \frac{-1.985984}{-0.2} \approx x_1 \cdot 9.92992 \]

Total Savings:

Combining this with the initial savings: \[ \text{Total Savings} = 125 + 9.92992 x_1 \]

Setting up the inequality:

To find out if this is enough for the vacation: \[ 125 + 9.92992 x_1 \geq 1364 \] \[ 9.92992 x_1 \geq 1364 - 125 \] \[ 9.92992 x_1 \geq 1239 \] \[ x_1 \geq \frac{1239}{9.92992} \approx 124.569 \]

Thus, the minimum amount they should start depositing in March must be approximately \( x_1 \geq 125 \) (rounding up as we need to consider whole dollars).

Total Amount if \( x_1 = 125 \):

Let’s calculate the total savings with \( x_1 = 125 \):

  • Month 1 (March): \( 125 \)
  • Month 2 (April): \( 125 \times 1.2 = 150 \)
  • Month 3 (May): \( 150 \times 1.2 = 180 \)
  • Month 4 (June): \( 180 \times 1.2 = 216 \)
  • Month 5 (July): \( 216 \times 1.2 = 259.2 \)
  • Month 6 (August): \( 259.2 \times 1.2 = 311.04 \)

Now summing these:

  • Total deposits = \( 125 + 150 + 180 + 216 + 259.2 + 311.04 \approx 1241.24 \)
  • Adding the initial savings: \( 125 + 1241.24 = 1366.24 \)

Conclusion:

  • If they deposit $125, they will have approximately $1366, which is LESS than $1364.
  • The vacation costs $1364.

Therefore, they would not have enough for their trip.

Final Calculation:

  • They need approximately: \( 1364 - 1366.24 = 2.24 \)
  • Rounding up, they will need at least $3 more.

So the correct response is: A. No, they need $3 more.

round to the nearest dollar

Thank you for your patience! Let's clarify the results with correct calculations and round to the nearest dollar.

Summary of Previous Calculations

  • The total cost of the vacation: $1364
  • Initial amount saved by the family: $125

Monthly Savings

Let’s denote the initial deposit (in March) as \( x_1 = 125 \).

  1. Month 1 (March): Deposit = $125
  2. Month 2 (April): Deposit = \( 125 \times 1.2 = 150 \)
  3. Month 3 (May): Deposit = \( 150 \times 1.2 = 180 \)
  4. Month 4 (June): Deposit = \( 180 \times 1.2 = 216 \)
  5. Month 5 (July): Deposit = \( 216 \times 1.2 = 259.2 \)
  6. Month 6 (August): Deposit = \( 259.2 \times 1.2 = 311.04 \)

Total Deposits Calculation

Now, summing all the deposits:

  • Total deposits \( = 125 + 150 + 180 + 216 + 259.2 + 311.04 \)

Calculating this: \[ = 125 + 150 + 180 + 216 + 259.2 + 311.04 \] \[ = 125 + 150 = 275 \] \[ = 275 + 180 = 455 \] \[ = 455 + 216 = 671 \] \[ = 671 + 259.2 = 930.2 \] \[ = 930.2 + 311.04 = 1241.24 \]

Adding the initial amount: \[ \text{Total Savings} = 125 + 1241.24 = 1366.24 \]

Comparison with Vacation Cost

The total amount they would have is approximately $1366 when rounded down, against the vacation cost of $1364.

Required Amount

  • Amount needed for vacation: $1364
  • Total they have: $1366

Calculating how much more they need: \[ 1364 - 1366.24 = -2.24 \]

Since they already have enough, and rounding to the nearest dollar:

Final Result

Yes, they will have enough money. They do not need more; in fact, they have approximately $2 left over after the trip expenses.

So, in response to the original question: B. Yes, they will have enough money.

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